Consider a sinusoidal input
| (4.1) |
The Laplace transform of the above equation yields
Consider the standard first order transfer function given below
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(4.3) |
Replacing the value of U(s) from equation 4.2, we get
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(4.4) | |
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(4.5) |
Taking Laplace Inverse, we get
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(4.6) |
The above equation has an exponential term
. Hence, for large value of time, its value will
approach to zero and the equation will yield a pure sine wave. One can also use trigonometric identities to make the equation
look more simple.
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(4.7) |
where,
| (4.8) |
By observing the above equation, one can easily make out that for a sinusoidal input the output is also sinusoidal
but has some phase difference.
Also, the amplitude of the output signal,
, has become a function of the input signal frequency,
.
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(4.9) |
The amplitude ratio (AR) can be calculated by dividing both sides by the input signal amplitude A.
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(4.10) |
Dividing the above equation by the process gain K yields the normalized amplitude ratio
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(4.11) |